If water with a mass of 0.755 absorbs 0.954j of heat, how much will its temperature increase?
a. 0.221
b. 0.302
c. 0.095
c. 0.564

B. 0.302.

Explanation:

Q = m.c.ΔT,

where, Q is the amount of heat absorbed by water (Q = 0.954 J).

m is the mass of water (m = 0.755 g).

c is the specific heat capacity of water (c = 4.186 J/g.°C).

ΔT is the temperature difference (final T - initial T) (ΔT =  ??? °C).

∴ ΔT = Q/m.c = (0.954 J)/(0.755 g)(4.186 J/g.°C) = 3.018 °C ≅ 3.02 °C.

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