What mass of ammonium hydroxide is produced when 34 grams of ammonium chloride are added to an excess of potassium hydroxide?

NH4Cl + KOH → NH3 + KCl + H2O  

(34 g NH4Cl) / (53.4917 g NH4Cl/mol) = 0.6356 mol NH4Cl  

(37 g KOH) / (56.10569 g KOH/mol) = 0.6595 mol KOH  

0.6356 mole of NH4Cl would react completely with 0.6356 x (1/1) = 0.6356 mole of KOH, but there is more KOH present than that, so KOH is in excess and NH3Cl is the limiting reactant.  

(0.6356 mol NH4Cl) x (1 mol NH3 / 1 mol NH4Cl) x (17.03056 g NH3/mol) = 11 g NH3

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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