According to bronsted-lowry definition of acids and bases what substances form when hci dissociates in water

So the Bronsted-Lowry definition of acid and bases states that an acid is a subtance that can donate a proton to another substance in a chemical reaction, while a base is a substance that can accept a proton from another substance in a chemical reaction.

It also states that the products that are formed from these acids and bases reacting are called conjugate acids and bases. Where a conjugate acid is define as an acid generated as a result of a base accepting a proton, while a conjugate base is defined as the base generated as a result of an acid donating a proton.

With this is in mind, what substances form when HCl dissociates in water?

Here is the reaction:

HCl + H2O ⇒ H3O+ + Cl-

The substances that form are H3O+ which is a conjugate acid and Cl- which is a conjugate base, all according to the definition of a Bronsted-Lowry acid and base.

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

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