Asolution contains 0.140 mol kcl in 2.100 l water. what is the concentration of kcl in g/l?

~0.0667 g/l
~0.294 g/l
~4.95 g/l

≈ 4.95 g/L

The molar mass of KCl = 74.5 g/mole

Therefore; 0.140 moles will be equivalent to ;

 = 0.140 moles × 74.5 g/mole

 = 10.43 g

Concentration in g/L

   = mass in g/volume in L

   = 10.43/2.1

   =  4.9667

personal, she chose to do it.