A10 l container holds 4 moles of gat at a pressure of 305 kpa. what is the temperature in kelvins?

91.768 K

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas in K.  

The temperature of the gas = PV/nR.

P = 305.0 kPa/101.325 = 3.01 atm, V = 10.0 L, R = 0.082 L.atm/mol.K, n = mass/molar mass = 4.0 mol.

∴ T = PV/nR = (3.01 atm)(10.0 L)/(4.0 mol)(0.082 L.atm/mol.K) = 91.768 K.

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