How to oxidize and reduce the following reactions

In 1st case hydrogen has oxidized.

In 2nd case the same has happened hydrogen.

In 3rd one Sb has oxidized...

Addition of oxygen or removal of hydrogen is known as oxidation

your answer would be “dry”

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.