When 6.0 mol al react with 13 mol hcl, what is the limiting reactant, and how many moles of h2 can be formed? 2al + 6hcl → 2alcl3 + 3h2

Explanation:

Part A: what is the limiting reactant?

1) Balanced chemical equation: given

2) Stoichiometric mole ratio:

Use the coefficients of the balanced equation:

3) Compare the stoichiometric mole ratio of the reactants with their actual ratio:

Since the actual ratio indicates that there is a greater number of moles of Al (0.46) per mol of Cl than what is required by the stoichiometric ratio(0.33), Al is in excess and HCl is the limiting reactant.

the limiting reactant is HCl.

Part B. How many moles of H₂ are formed?

3. Determine how many moles of H₂ can be formed

        6 mol HCl / 3 mol H₂ = 13 mol HCl / x

        ⇒ x = 13 mol HCl × 3 mol H₂ / 6 mol HCl = 6.5 mol H₂.

The answer must be reported with two significant digits, such as the data are given.

6.5 moles of H₂ are formed

can you list the answers so i can answer