Xis an oxide of nitrogen

2.30g of x contains 3.01 x 10 22 molecules of x calculate the molar mass of x

M 6,022*10^22 molecules
2,30g 3,01*10^22 molecules

or 1 mole has 6,022*10^22 molecules so (2,30/Molar mass) = nr of moles with 3,01*10^22 molecules
which will lead to the same thing.
M= 4,6

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