60 grams of ice will require calories to raise the temperature 1°c.

60 grams of ice will require 30.26 calories to raise the temperature 1°C.

Explanation:

The amount of heat (Q) to raise the temperature of 60.0 g of ice by 1°C can be calculated from:

Q = m.c.ΔT,

where, Q is the amount of heat released or absorbed by the system.

m is the mass of the ice (m = 60.0 g).

c is the specific heat capacity of ice (c = 2.108 J/g.°C).

ΔT is the temperature difference (ΔT = 1.0 °C).

∴ Q = m.c.ΔT = (60.0 g)(2.108 J/g.°C)(1.0 °C) = 126.48 J.

It is known that 1.0 cal = 4.18 J.

∴ Q = (126.48 J)(1.0 cal / 4.18 J) = 30.26 cal.

that's what i got you can count the number of atoms