How many moles of p4 would you need to produce 34 g of ph3?

p4(s) + 6 h2(g) → 4 ph3(g)

0.25 mol
0.5 mol
1 mol
4 mol

Molecular weight of P (Phosphorous) = 30.97g/mol

Hydrogen is just 1 g/mol.

How many moles is 34g of PH3?

Get the weight of PH3 (30.97 + (3X1)) = 33.97g/mol

So 34g/33.97g/mol = 1.0009 moles.

I bet for this problem it's easier to round this to 1.

If you look at just the moles in the equation:

P4(s) + 6 H2(g) → 4 PH3(g)

OR

1 + 6 → 4

If 1 (P4) gives us 4 (PH3), what gives us 1 (PH3)?

1/4 = x/1

solve for x

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )

the answer is 75.0%.