How many moles of sodium nitrate nano3 would be produced from the complete reaction of 253 g sodium chromate na2cro4

= 3.12 moles of NaNO3

The equation for the reaction is;

Pb(NO3)2+Na2CrO4 → PbCrO4+2NaNO3

Molar ratios in the reaction are ; 1 : 1 : 1 : 2

Which means; One mole of (Na2CrO4) produces two moles of (NaNO3)

We can calculate the number of moles of Na2CrO4,

Moles (na2CrO4) = 253g /162

                             = 1.56 moles

Moles of NaNO3 will be;

 = 1.56 moles x 2 = 3.12 moles

Therefore, the moles of NaNO3 that will be produced will be 3.12 moles

so what is the problem with your lab report and whats the subject of the lab report? i will you