Ihave no idea how to do this someone ! it’s stoichiometry. caco3 + 2hcl --> cacl2 + co2 + h2o if 20.8 grams of calcium carbonate reacts with excess hcl, how many moles of calcium chloride are produced?

Take stoichiometry In to consideration. The ratio of CaCO3 to CaCl2 is 1:1

Therefore the amount of moles in CaCO3 is same as moles in CaCl2.

Calculate the moles of CaCO3 using the equation n =m/M where

n = moles

m = mass

M =molar mass

And find the moles which is 0.208 mol in this case.

Therefore the moles of CaCl2 is also 0.208mol

(lol... Um doing all ur chemistry sums..)