If i initially have a gas at a pressure of 2 atm, a volume of 3 liters, and a temperature of 100k, and then i raise the pressure to 6atm and increase the temperature to 200k, what is the new volume?

2 L  

Step-by-step explanation:

We have two pressures, two temperatures, and one volume.

This looks like a question in which we can use the Combined Gas Law to calculate the volume.

p₁V₁/T₁ = p₂V₂/T₂     Multiply both sides by T₂

p₁V₁T₂ = p₂V₂           Divide each side by p₂

          V₂ = V₁ × p₁/p₂ × T₂/T₁  

Data:

p₁ = 2 atm;  V₁ = 3 L;  T₁ = 100 K

p₂ = 6 atm; V₂ = ?;     T₂ = 200 K

Calculation:

V₂ = 3 L × (2 atm/6 atm) × (200 K/100 K)  

V₂ = 3 L × ⅓ × 2  

V₂ = 2 L  

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.

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