If 18.9 ml of 0.800 m hcl solution are needed to neutralize 5.00 ml of a household ammonia solution, what is the molar concentration of the ammonia?

3.024 M.

Explanation:

Based on at the neutralization, the no. of millimoles of acid (HCl) is equal to the no. of millimoles of the base (ammonia).

(MV)HCl = (MV)ammonia

M of HCl = 0.80 M & V of HCl = 18.9 mL.

M of ammonia = ??? M & V of ammonia = 5.0 mL.

∴ M of ammonia = (MV)HCl / V of ammonia = (0.80 M)(18.9 mL) / (5.0 mL) = 3.024 M.

The answer is bhope this

27. =3,500,000 x 4,000 = 14,000,000,000