Predict the mass of iron (iii) sulfide produced when 3.0 g of iron filings react completely with 2.5 g of yellow sulfur solid, s8(s).
a) 1.5g fe2s3
b) 2.5g fe2s3
c) 3.5g fe2s3
d) 5.5g fe2s3

D) 5.5 g Fe₂S₃.

Explanation:

No. of moles of Fe filings (3.0 g) = mass /atomic mass = (3.0 g) / (55.845 g/mol) = 0.0537 mol.

No. of moles of yellow sulfur solid (2.5 g) = mass / molar mass = (2.5 g) / (256.52 g/mol) = 0.009746 mol.

The theoretical ratio of (Fe: S₈) is (16: 3) which is 5.333.

The actual ratio of the reactants (Fe:S₈) is (0.0537 mol: 0.009746 mol) which is 5.5.

Using cross multiplication:

3.0 moles of S₈ produces → 8.0 moles of Fe₂S₃, from the stichiometry,

0.009746 moles of S₈ produces → ??? moles of Fe₂S₃.

The mass of the the produced Fe₂S₃ =  no. of moles x molar mass = (0.026 mol)(207.9 g/mol) = 5.405 g ≅ 5.5 g.

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying