Ca(oh)2 + 2hno3 -> ca(no3)2+ 2h2o how many moles nitric acid is needed to make 22.8 g of water?

1.27 mol HNO₃

Explanation:

We know we will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

M_r:                                                           18.02

          Ca(OH)₂ + 2HNO₃ ⟶ Ca(NO₃)₂ + 2H₂O

m/g:                                                             22.8  

2. Calculate the moles of H₂O

Moles of H₂O = 22.8 g H₂O × (1 mol H₂O/18.02 g H₂O)

                      = 1.265 mol H₂O

3. Calculate the moles of HNO₃

The molar ratio is 2 mol HNO₃/2 mol H₂O.

Moles of HNO₃ = 1.265 mol H₂O × (2 mol HNO₃/2 mol H₂O)

                         = 1.27 mol HNO₃

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