The aquation of tris(1,10-phenanthroline)iron(ii) in acid solution takes place according to the equation: fe(phen)32+ + 3 h3o+ + 3 h2o → fe(h2o)62+ + 3 phenh+. if the activation energy, ea, is 126 kj/mol and the rate constant at 30°c is 9.8 × 10-3 min-1, what is the rate constant at 35°c? the aquation of tris(1,10-phenanthroline)iron(ii) in acid solution takes place according to the equation: fe(phen)32+ + 3 h3o+ + 3 h2o → fe(h2o)62+ + 3 phenh+. if the activation energy, ea, is 126 kj/mol and the rate constant at 30°c is 9.8 × 10-3 min-1, what is the rate constant at 35°c? 4.4 × 10-3 min-1 4.5 × 101 min-1 2.3 × 102 min-1 2.2 × 10-2 min-1

2.2 × 10⁻² min⁻¹  

Step-by-step explanation:

We can use the Arrhenius equation  

Data:

k₁ = 9.8 × 10⁻³ min⁻¹; k₂ = ?

Eₐ = 126 kJ·mol⁻¹

T₁ = 30 °C; T₂ = 35°C  

Calculations:

(a) Convert temperatures to kelvins.

T₁ = (30 + 273.15) K = 303.15  K

T₂ = (35 + 273.15) K = 308.15  K

(b) Activation energy

k₂ = 9.8 × 10⁻³× 2.25

    = 0.022 min⁻¹

    = 2.2 × 10⁻² min⁻¹

what are the óptions. pléase list them

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72