List the number of each type of atom on the left side of the equation 2c10h22(l)+31o2(g)→20co2(g)+22h2o(g )

There are 20 carbons atoms, 62 oxygen atoms and 44 carbon atoms on the left side of the equation.

Explanation:

In the given chemical reaction:

Reactants side = Left side

Number of atoms =

Coefficient × Number of atoms of an element in a unit molecular formula

Number of carbon atoms = 2 × 10 = 20

Number of oxygen atoms = 31 × 2 = 62

Number of hydrogen atoms =  2 × 22 = 44

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm