Find the binding energy of the tritium nucleus (3 1h) in mev's.(use three significant figures in the answer) mev.

The actual binding energy is 8.48 Mev

The nucleus of tritium contains one proton and two neutrons,

Therefore; For the Tritium nucleus, the binding energy may be computed as shown below:

Total mass of 1 protons            = 1 × 1.00728 = 1.00728 amu

Total mass of 2 neutrons           = 2 × 1.00866 = 2.01732 amu

Total mass of nucleons                          =  3.02460amu

Atomic mass of tritium                            =  3.01605 amu

Mass defect Dm                                        = 0.00855 amu

But; 1 amu =931.5  MeV

Thus; Binding energy of Tritium = 0.00855 amu × 931.5  MeV/amu

                                                     = 7.964325 MeV, approximately closer to the actual 8.48 MeV.

a. hope i'm right

explanation: