Water (2510 g ) is heated until it just begins to boil. if the water absorbs 5.09×105 j of heat in the process, what was the initial temperature of the water?

Ans: Initial temperature of water = 51.5 C

Given:

Mass of water (m) = 2510 g

Heat absorbed by water (q) = 5.09*10⁵ J

Final temperature of water = boiling point = T2 = 100 C

To determine:

The initial temperature, T1

Explanation:

Heat absorbed by water is given as:

q = mc(T2-T1)

c = specific heat of water = 4.18 J/gC

5.09*10⁵ = 2510 g*4.18 J/gC *(100-T1)

T1 = 51.5 C

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explanation: