How many atoms of mg are present in 97.22 grams of mg? 6.022 × 1023 2.408 × 1024 4.818 × 1024 5.855 × 1025

Option (b) is the correct answer.

Explanation:

It is given that mass of Mg is 97.22 g and it is known that molar mass of Mg is 24.305 g/mol.

So, calculate the number of moles as follows.

          No. of moles =

                                 =  

                                 = 4 mol

Also, it is known that 1 mole has atoms/mol. Therefore, calculate the number of atoms in 4 mol as follows.

               = atoms

or,            = atoms

Thus, we can conclude that there are atoms in 97.22 grams of Mg.

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3