What volume of argon gas is equal to 1.60 grams of argon

0.908 L.

Explanation:

Firstly, we should calculate the number of moles of 1.60 g argon.n of Ar = mass / molar mass of Ar = (1.60 g) / (39.948 g/mol) = 0.04 mol.|t is established  and known that the molar volume of a gas at STP (Standard Temperature and Pressure) is equal to 22.4 L for 1 mole of any ideal gas at a temperature of 273.15 K and a pressure of 1.00 atm.

using cross multiplication:

1.0 mole of Ar gas will occupy → 22.7 L

0.04 mole of Ar gas will occupy → ??? L

∴ The volume  occupied by Ar = (0.04 mole) (22.7 L) / (1.0 mole) = 0.908 L.

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