How many moles of sulfuric acid (h2so4) are needed to react completely with 6.8 moles of lithium hydroxide (lioh)? 2lioh + h2so4 → li2so4 + 2h2o a) 3.4 mol h2so4 b) 6.8 mol h2so4 c) 10.2 mol h2so4 d) 13.6 mol h2so4 a) 3.4 mol h2so4

A) 3.4 mole of H₂SO₄.

Explanation:

From the stichiometry of the reaction: 2 LiOH + H₂SO₄ → Li₂SO₄ + 2 H₂OIt is clear that 2.0 moles of LiOH reacts with 1.0 mole of H₂SO₄ to produce 1.0 mole of Li₂SO₄ and 2.0 moles of H₂O.

Using cross multiplication:

1.0 mole of H₂SO₄ reacts completely with → 2.0 moles of LiOH

??? mole of H₂SO₄ are needed to react completely with → 6.8 moles of LiOH

The number of moles of H₂SO₄ = (1.0 x 6.8) / (2.0) = 3.4 mole of H₂SO₄.

What do you mean by that? like the contents? the thc level?