Which set of numbers gives the correct possible values of l for n = 2? 0 0, 1 0, 1, 2 0, 1, 2, 3

The answer is 0 and 1

This is because for a given principal quantum number, n, the corresponding set of angular quantum numbers, l, is equivalent to a range between 0 and (n-1). For n=2, (n-1) is equal to 1, so the range is 0 and 1. The magnetic quantum number, m, can be determined by a range from -l to +l. So for this example, m = -1, 0, 1.