Acompound was analyzed and found to contain 13.5 g ca, 10.8 g o, and 0.675 g h. what is the empirical formula of the compound?

The empirical formula of the compound is

Explanation:

To find the empirical formula of the compound, we follow following steps:

To calculate the number of moles, we use the formula:

Molar mass of calcium = 40 g/mol

Given mass of calcium = 13.5 g

Putting values in above equation, we get:

Molar mass of oxygen = 16 g/mol

Given mass of oxygen = 10.8 g

Putting values in above equation, we get:

Molar mass of hydrogen = 1 g/mol

Given mass of hydrogen= 0.675 g

Putting values in above equation, we get:

For Ca =

For H =

For O =

The ratio of Ca : O : H = 1 : 2 : 2

The formula becomes:

Hence, the empirical formula of the compound is

the answer is c i believe