How many moles of carbon dioxide gas can be produced when 12.8 moles of benzene (c6h6) react with excess oxygen? unbalanced equation: c6h6 + o2 → co2 + h2o show, or explain, all of your work along with the final answer.

76.8 mole

Explanation:

Firstly, the balanced equation of reacting benzene with excess oxygen is:

2C6H6 + 15O2 → 6H2O + 12CO2

It is clear that every two moles of benzene react with 15 mole of oxygen to produce 6 moles of water and 12 mole of CO2Which means that 2 moles of benzene give 12 moles of CO2So, n(C6H6)/2 = n(CO2)/12which give n(C6H6) = n(CO2)/6n(CO2) = n(C6H6) x 6 = 12.8 x 6 = 76.8 mole

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