How many grams of lithium chloride must decompose to produce 30.3 grams of lithium metal? show all steps of your calculation as well as the final answer. 2licl > 2li+cl2

185.05 g.

Explanation:

Firstly, It is considered as a stichiometry problem.From the balanced equation: 2LiCl → 2Li + Cl₂It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.n = (30.3 g) / (6.941 g/mole) = 4.365 moles.Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.Using cross multiplication:2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.??? moles of LiCl → 4.365  moles of Li.The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).Molar mass of LiCl = 42.394 g/mole.mass = n x molar mass = (4.365 x 42.394) = 185.05 g.

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