Use the periodic table to find the charge of the ion that each atom is most likely to form. the charge of a sulfur (s) ion is the charge of a potassium (k) ion is the charge of a boron (b) ion is the charge of an iodine (i) ion is the charge of a bromine (br) ion is

Explanation:

Elements that gain electrons will have a negative charge and elements that lose electrons will have a positive charge.

Atomic number of sulfur (S) atom is 16 and its electronic distribution is 2, 8, 6. In order to completely fill its octet sulfur will gain 2 electrons and thus it forms ion.Atomic number of potassium (K) atom is 19 and its electronic distribution is 2, 8, 8, 1. In order to stabilize its octet potassium will lose 1 electron and thus it forms ion.Atomic number of boron (B) atom is 5 and its electronic distribution is 2, 3. In order to stabilize its octet boron will lose 3 electrons and thus it forms ion.Atomic number of iodine (I) atom is 53 and it has 7 valence electrons. In order to stabilize its octet iodine will gain 1 electron and thus it forms ion.Atomic number of bromine (Br) atom is 35 and it also has 7 valence electrons. In order to stabilize its octet bromine will gain 1 electron and thus it forms ion.

Answer is to avoid experimental error