In a solution at 25°c, the [h+] is 3.5 × 10−6 m. what is the [oh−]?

[OH-] = 2.857 x 10∧-9

Explanation:

At 25 °C; the product of [H+] and [OH-] is 10∧-14

[H+] [OH-] = 10∧-14

and [H+] = 3.5 x 10∧-6

[OH-] = 10∧-14 / (3.5 x 10∧-6) = 2.857 x 10∧-9.

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

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