If in dehydration experiment of 20.0 ml cyclohexanol, 12.0 g cyclohexene obtained, calculate the theoretical and percentage of cyclohexene

Hey there!:

Density of cyclohexanol = 962Kg/m³ = 962*0.001g/cm³ =0.962g/ml

mass = density *volume= 0.962*20 = 19.24grams

% yield =

Number of moles of product produced *100 / ( number of moles of reactant taken)

moles of cyclohexanol = 19.24/100.158 = 0.192moles

moles of moles of cyclohexene = 12/82.143 = 0.146 moles

% yield =  0.146*100/0.192 = 76.04%

Hope that helps!

c. is the answer

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