A13.00 g sample of citric acid reacts with an excess of baking soda what is the theoretical yield of carbon dioxide

8.934 g

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:        192.12                                                                   44.01

            H₃C₆H₅O₇ + 3NaHCO₃ ⟶ Na₃C₆H₅O₇ + 3H₂O + 3CO₂

m/g:        13.00

For ease of writing, let's write H₃C₆H₅O₇ as H₃Cit.

(a) Calculate the moles of H₃Cit

n = 13.00 g  × (1 mol H₃Cit /192.12 g H₃Cit)

n = 0.067 67 mol H₃Cit

(b) Calculate the moles of CO₂

The molar ratio is (3 mol CO₂/1 mol H₃Cit)

n = 0.067 67 mol H₃Cit × (3 mol CO₂/1 mol H₃Cit)

n = 0.2030 mol CO₂

(c) Calculate the mass of CO₂

m = 0.2030 mol CO₂ × (44.01 g CO₂/1 mol CO₂)

m = 8.934 g CO₂

no

explanation:

go away, people want answers, not to hook up

chemists can use the electron cloud model to assign electrons to different atomic orbitals. atomic orbitals also explain the patterns in the periodic table

explanation: