For each mole of glucose (c6h12o6) completely oxidized by cellular respiration, how many moles of co2 are released in the citric acid cycle (see the figure)? the figure shows the scheme of the citric acid cycle. starting from acetyl coa, it transforms into citrate, then isocitrate, then alpha-ketoglutarate, then succynil coa, then succinate, then fumarate, then malate, then oxaloacetate and then forms a cycle with the transformation of oxaloacetate into citrate in the presence of acetyl coa. one molecule of co2 is formed at the stage of formation of alpha-ketoglutarate and one is formed at that of succinyl coa. for each mole of glucose (c6h12o6) completely oxidized by cellular respiration, how many moles of co2 are released in the citric acid cycle (see the figure)? 2 3 4 6 12

Four carbondioxide molecules are formed in citric acid cycle.

One mole of glucose when completely oxidized by cellular respiration produces 4 molecules of CO2 in the citric acid cycle. Two acetyl-CoA molecules enter the citric acid cycle and each acetyl-CoA molecule has two carbon atoms which produces four carbon dioxide molecules.

Two carbon dioxide molecules are formed in the conversion of pyruvic acid to acetyl-CoA so six carbon dioxide molecules are formed with addition of above four carbondioxide molecules so we can say that in citric acid cycle, four carbondioxide molecules are formed.

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Step-by-step explanation:

The reactions are:

Glycolysis:                      1 glucose ⟶ 2 pyruvate

Link reaction:         2 × [1 pyruvate ⟶ 1 acetyl CoA]

Citric acid cycle: 2 × [1 AcetylCoA ⟶ 2 CO₂]

Now, add the reactions, cancelling species that occur on both sides of the reaction arrow,

             1 glucose ⟶ 2 pyruvate

           2 pyruvate ⟶ 2 acetyl CoA

        2 AcetylCoA ⟶ 4 CO₂

Overall : 1 glucose ⟶ 4 CO₂

For each mole of glucose, four molecules of CO₂ are released in the citric acid cycle.

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