Which of the following is a valid mole ratio from the balanced equation 2fe2o3 + 3c → 4fe + 3co2? a. four moles of c over three moles of f e b. two moles of f e two o three over four moles of c c. three moles of c over four moles of c o two d. four moles of f e over three moles of c o two

D. four moles of F e over three moles of C O two

Explanation:

I legit took the exam, used this "B. two moles of F e two O three over four moles of C" and got it wrong. If you go to other Q/A sites, google, research, or do anything of the sort you will find conflicting answers. My advicce is do the math and check it if you don't believe me. All I can tell yoi is that this: Four moles of "Fe" over three moles of C O two-- IS THE RIGHT ANSWER. All I ask in return is that you 5 star this when you inevitably get it right. I don't want anyone else to get this wrong, that would suck.

the answer is true.

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying