How many moles of calcium oxide will be produced when 1.6 moles of iron(iii)oxide reacts with calcium phosphate according to the following (unbalanced) reaction: fe2o3 + ca3(po4)2 —> fe(po4) + cao

4.8 mol

Step-by-step explanation:

The balanced equation is

Fe₂O₃ + Ca₃(PO₄)₂ ⟶2FePO₄ + 3CaO

You want to convert moles of Fe₂O₃ to moles of CaO.

The molar ratio is 3 mol CaO:1 mol Fe₂O₃.

Moles of CaO = 1.6 mol Fe₂O₃ × (3 mol CaO/1 mol Fe₂O₃)

Moles of CaO = 4.8 mol CaO

The reaction will produce 4.8 mol of CaO.

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