How many grams of co are needed to react with an excess of fe203 to produce 156.2 g fe? show your work. fe203 (s) + 3 co (g) 3 co2 (g) 2 fe (s)

The reaction is given as

Fe2O3 (s)+ 3CO(g)--->3CO2(g)+ 2Fe(s)

No.of moles=mass in gram/molar mass

As for Fe mole =156.2g/55.847=2.7969~2.797

The ratio b/w CO and Fe is 3:2

Moles of CO needed= 2.797x3/2=4.1955

Mass of CO needed= 4.195mol x 28.01g/mol= 117.515g

i think that the answer is c