How many particles of bacl2 reacted if 1.53 mol of it were consumed? a) 2.54 x 10–24 particles bacl2 b) 6.83 x 10–24 particles bacl2 c) 3.43 x 101 particles bacl2 d) 9.21 x 1023 particles bacl2

- D) particles .

Solution:- There are 1.53 moles of the compound are given and it asks to calculate the number of particles.

To calculate the number of particles we multiply the moles with Avogadro number.

=

So, the D is the right choice.

pure substance: iron,copper

impure substance: water,charcoal

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.