Fe2o3 + h2so4à fe2(so4)3 + h2o for this unbalanced chemical equation, what is the coefficient for water when the equation is balanced?

3

Explanation:

Put a 1 in front of the most complicated-looking formula [Fe₂(SO₄)₃]:

Fe₂O₃ + H₂SO₄ ⟶ 1Fe₂(SO₄)₃+ H₂O

Balance Fe:

Put a 1 in front of Fe₂O₃.

1Fe₂O₃ + H₂SO₄ ⟶ 1Fe₂(SO₄)₃+ H₂O

Balance S:

Put a 3 in front of H₂SO₄.

1Fe₂O₃ + 3H₂SO₄ ⟶ 1Fe₂(SO₄)₃+ H₂O

Balance O.

We have fixed 15 O on the left but only 12 O on the right. Put a 3 in front of H₂O.

1Fe₂O₃ + 3H₂SO₄ ⟶ 1Fe₂(SO₄)₃+ 3H₂O

Every formula now has a coefficient. The equation should be balanced.

Check:

Atom  On the left  On the right

  Fe             2                   2

  O             15                  15

  H              6                    6

  S              3                     3

The balanced equation is

Fe₂O₃ + 3H₂SO₄ ⟶ Fe₂(SO₄)₃+ 3H₂O

The coefficient of H₂O is 3.

lol for the pointsss