How many grams of hydrochloric acid will react completely with a block of gold that is 3.2 cm by 3.8 cm by 2.8 cm, if the density of gold is 19.3 g/ml? show all steps of your calculation as well as the final answer. au+hcl -> aucl2+h2

243.50 grams of hydrochloric acid will react completely with a block of gold.

Explanation:

Mass of gold = m

Length of gold block = l =  3.2 cm

Breadth of gold block = b = 3.8 cm

height of gold block = h = 2.8 cm

Volume of the gold = V = l × b × h = 3.2 cm × 3.8 × cm × 2.8 cm

V = ()

Density of gold = d = 19.3 g/ml

Moles of gold =

According to recation, 1 mole gold reacts with 2 moles of HCl .Then 3.3357 moles of gold will ":

of HCl

Mass of 6.6713 moles of HCl =

243.50 grams of hydrochloric acid will react completely with a block of gold.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.