Determine total h for bonds broken and formed, the overall change in h, and the final answer with units. is it endothermic or exothermic? reaction: 2h2(g) +o2(g) -> 2h2o^(g) given: h-h 436 o+o 499 o-h 463

E(Bonds broken) = 1371 kJ/mol reactionE(Bonds formed) = 1852 kJ/mol reactionΔH = -481 kJ/mol. The reaction is exothermic.Explanation

2 H-H + O=O → 2 H-O-H

There are two moles of H-H bonds and one mole of O=O bonds in one mole of reactants. All of them will break in the reaction. That will absorb

E(Bonds broken) = 2 × 436 + 499 = 1371 kJ/mol reaction.ΔH(Breaking bonds) = +1371 kJ/mol

Each mole of the reaction will form two moles of water molecules. Each mole of H₂O molecules have two moles O-H bonds. Two moles of the molecule will have four moles of O-H bonds. Forming all those bond will release

E(Bonds formed) = 2 × 2 × 463 = 1852 kJ/mol reaction.ΔH(Forming bonds) = - 1852 kJ/mol

Heat of the reaction:

is negative. As a result, the reaction is exothermic.

Ithinks its false. tell me if im wrong

The correct answer should be "electrons orbit the nucleus in circular motions exactly as shown on the classic bohr model."