For the equation 2no + o2 → 2no2, how many liters of nitrogen dioxide would be formed from 56 liters of nitrogen monoxide at stp? (assume you have plenty of oxygen)

49.30 L

Explanation:

1. Write the chemical equation.

Ratio:    2 L                 2 L

           2NO +O₂ ⟶ 2NO₂

V/L:       56

2. Calculate the volume of NO₂.

We can use Gay-Lussac's Law of Combining Volumes to solve this problem.

According to the law, 2 L of NO₂ are formed from 2 L of NO.

Then, the conversion factor is (2 L NO₂/2 L NO).

Volume of NO₂ = 56 × 2/2

Volume of NO₂ = 56 L

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