What is the balanced equation for the combustion of magnesium? a. mg (s) +o2 (g) > mgo(g) b. mg (s) +o2 (g) > mgo2(g) c. 2 mg (s) + o2 (g) > 2 mgo (s) d. mg (s) + 2 o2 (g) > mgo4^2- (aq)

option a

mg atomic number is 12

the electronic configuration is 2, 8, 2

Oxygen atomic number is 8

the electronic configuration is 2,7

the magnesium will try to give away 2 electron to get to the form of noble gas configuration, hence oxygen needs one more to get to noble gas hence it will take two elements of oxygen to form MgO.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

2b2t

explanation:

2b2t