All waves on the electromagnetic spectrum travel at the same speed in a vacuum. the speed of these waves in a vacuum is 3x108 m/s. as the wavelength of wave doubles, how does the speed and frequency of the wave change

The wavelength (λ), speed (c) and the frequency (ν) of a wave are related as:

ν = c/λ  (1)

The speed of the waves is a constant in vacuum i.e. it remains at 3*10⁸ m/s. therefore, it will not change with changes in wavelength or frequency.

Let us consider:

ν1 = initial frequency and λ1 = initial wavelength

ν2 = final frequency and λ2 = final wavelength = 2(λ1)

based on equation (1) we have:

ν1/ν2 = λ2/λ1 = 2(λ1)/λ1 = 2

therefore: ν2 = 1/2(ν1)

The frequency will get reduced by one-half as the wavelength doubles.

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml