Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6li (s) + n2 (g) → 2li3n (s) in a particular experiment, 4.00-g samples of each reagent are reacted. the theoretical yield of lithium nitride is g.

6.69 g.

Make sure the chemical equation is balanced:

Assuming that one mole of N₂ is consumed. How many grams of each reactant will that take? Refer to a periodic table for data on atomic mass.

4.00 grams of each reactant are available. How many moles of N₂ can they consume?

However, only 0.09606 moles of the reaction is possible, since Li would have ran out before all 4.00 grams of N₂ are used up.

Each mole of the reaction makes 2 moles of Li₃N. 0.09606 moles of the reaction will produce 0.09606 × 2 × (3 × 6.94 + 14.01) = 6.69 grams of Li₃N.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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