How much heat is absorbed by a 56g iron skillet when its temperature rises from 7oc to 28oc?

The heat absorbed is calculated with the help of the formula,

Q = mCΔT

Q is heat absorbed, m is mass given as 56 gms, C is the specific heat of iron, that is, 0.449 J/g°C, and delta T is the change in temperature, which is 28 - 7 = 21°C

Thus, Q = 56 × 0.449 × 21 = 528 J

explanation:

i think option no d is the correct answer

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3