Part b (r)–3-chloro-2-methylhexane will undergo a nucleophilic substitution reaction in the presence of sodium ethoxide and ethanol. complete the mechanism for the sn2 reaction and draw the products of the reaction. draw all missing reactants and/or products in the appropriate boxes by placing atoms on the grid and connecting them with bonds and including charges where needed. indicate the mechanism by drawing the electron-flow arrows on the molecules. arrows should start on an atom or a bond and should end on an atom, bond, or where a new bond should be created.

In SN2 reaction the nucleophile will attack from back side and we will get product with inverted geometry

This is also known as Walden Inversion

The mechanism will be

See explanation

Explanation:

First, we need to remember what a SN2 reaction mechanism consist.

The SN2 reaction involves displacement of a leaving group by a nucleophile. This reaction works best with methyl, primary and secondary halides not too bulky, because bulky alkyl groups block the backside attack of the nucleophile.

Because of the backside attack of the nucleophile, inversion of configuration occurs always.

In this case, we can say that is reactant has a (R) configuration, the product will suffer an inversion, and become (S) in a nucleophylic reaction (it's formed an elimination product too).

Now, in the picture below you'll the mechanism, transition state and products of reaction: