Aballoon that had a volume of 3.50 l at 25.0°c is placed in a hot room at 40.0°c. if the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room? 2.19 l 3.33 l 3.68 l 5.60 l

The answer is C on edge!

Explanation:

C. 3.68

Explanation:

V1 / T1 = V2 / T2

3.50 / (25+273) = V2 / (40+273)

3.50(40+273) / (25+273) = V2

V2 = 3.676      3.676=3.68

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally