Chemistry, 28.06.2019 15:00 IsabelAyshi

Question: draw a valid lewis structure for the molecule ch3no in which there are no nonzero formal charges on any of the atoms. this structure should not include any bonds between n and o. what do you do with the oxygen?

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Answer from: pandamaknae2003

The mentioned molecule with formula, CH₃NO where no bond is found between N and O can be depicted as formamide is shown in the attachment below.

The formal charges = Number of valence electrons for the atom (V) - the number of electrons in lone pairs (N) - 1/2 (number of electrons in bond pairs, B)

FC = V - N - B/2

Thus, there is a need to calculate valence electrons, electrons in lone pairs, and the number of electrons in bond pairs for each atom in the mentioned molecule.

V or valence electrons on C = 4e, on H = 1e, on N = 5e, and on O = 6e.

N or electrons in lone pairs on C = 0e, on H = 0e, on N = 2e, and on O = 4e.

B or number of electrons in bond pairs for C = 8e, for H = 2e, for N = 6e, and for O = 4e.

Thus, the formal charges for each will be,

C = 4 - 0 - (8/2) = 0

H = 1 - 0 - (2/2) = 0

N = 5 - 2 - (6/2) = 0

O = 6 - 4 - (4/2) = 0

Lewis dot structure for the given molecule is given in the attachment below:

Question: draw a valid lewis structure for the molecule ch3no in which there are no nonzero formal

Answer from: kelbruggie

Answer : The Lewis-dot structure of CH_3NO is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, CH_3NO

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in CH_3NO = 4 + 3(1) + 5 + 6 = 18

According to Lewis-dot structure, there are 12 number of bonding electrons and 6 number of non-bonding electrons.

Now we have to determine the formal charge for each atom.

Formula for formal charge :

$\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}$

$\text{Formal charge on O}=6-4-\frac{4}{2}=0$

$\text{Formal charge on C}=4-0-\frac{8}{2}=0$

$\text{Formal charge on N}=5-2-\frac{6}{2}=0$

$\text{Formal charge on }H_1=1-0-\frac{2}{2}=0$

$\text{Formal charge on }H_2=1-0-\frac{2}{2}=0$

$\text{Formal charge on }H_3=1-0-\frac{2}{2}=0$

Hence, the Lewis-dot structure of CH_3NO is shown below.

Answer from: Quest

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.

Answer from: Quest

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