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Chemistry, 28.06.2019 21:30 Maaaryyss

The following equation is one way to prepare oxygen in a lab. 2kclo3 → 2kcl + 3o2 molar mass info: mm o2 = 32 g/mol mm kcl = 74.55 g/mol mm kclo3 = 122.55 g/mol if 25.6 g of kcl are produced, then how many moles of kclo3 were consumed? 0.209 mol 0.687 mol 0.343 mol 0.172 mol

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The following equation is one way to prepare oxygen in a lab. 2kclo3 → 2kcl + 3o2 molar mass info:...
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