What is the molarity of 500 ml of a solution containing 85.0g agno3? a) 0.5 m b) 1.0 m c) 2.0 m d) 5.0 m

Consider the equation for calculating molarity: (no. of mole of solute)÷(volume of solution)

First, let's find the no. of mole of solute in AgNO3. As (no. of mole) = mass / molar mass

no. of mole of 85.0g of AgNO3 = 85.0/(107.9+14.0+16.0x3)

=0.5mol

Since the volume of the solution has to be in dm3, just divide the volume in cm3 by 1000 to get the volume in dm3.

Volume of solution = 500/1000

= 0.5 dm3

Therefore, the molarity is

0.5/0.5

=1.0M

The answer should be B.

ill try to . no promises tho.

explanation:

answer; natural resources;