What is the molarity of a saline solution that contains 0.900 g nacl (58.44 g/mol) dissolved in 100.0 ml of solution?

  The molarity  of a saline solution  that contain 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 ml solution is  0.15 M

  calculation

 Molarity = moles /volume  in liters

volume in  liters = 100.0 ml / 1000 = 0.1 L

 moles =  mass÷ molar mass

=  0.900 g ÷58.44 g/mol =0.015 moles

molarity  is therefore =   0.015 moles /  0.1 L =0.15 M

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